5x^2-28xy+32y^2=0

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Solution for 5x^2-28xy+32y^2=0 equation: 


Simplifying
5x2 + -28xy + 32y2 = 0

Reorder the terms:
-28xy + 5x2 + 32y2 = 0

Solving
-28xy + 5x2 + 32y2 = 0

Solving for variable 'x'.

Factor a trinomial.
(x + -4y)(5x + -8y) = 0


Subproblem 1
Set the factor '(x + -4y)' equal to zero and attempt to solve:

Simplifying
x + -4y = 0

Solving
x + -4y = 0

Move all terms containing x to the left, all other terms to the right.

Add '4y' to each side of the equation.
x + -4y + 4y = 0 + 4y

Combine like terms: -4y + 4y = 0
x + 0 = 0 + 4y
x = 0 + 4y
Remove the zero:
x = 4y

Simplifying
x = 4y

Subproblem 2
Set the factor '(5x + -8y)' equal to zero and attempt to solve:

Simplifying
5x + -8y = 0

Solving
5x + -8y = 0

Move all terms containing x to the left, all other terms to the right.

Add '8y' to each side of the equation.
5x + -8y + 8y = 0 + 8y

Combine like terms: -8y + 8y = 0
5x + 0 = 0 + 8y
5x = 0 + 8y
Remove the zero:
5x = 8y

Divide each side by '5'.
x = 1.6y

Simplifying
x = 1.6y
Solution
x = {4y, 1.6y}

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